STA301 GDB Fall 2020 Solution & Discussion

[+ M.Tariq Malik]

STA301 GDB Fall 2020 Solution & Discussion

skewed okay subsequently symmetrical distribution

in the case of symmetrical distribution

the empirical relation state that

those symmetrical distributions

mean

when our distribution is not symmetric

mean is greater than median and median

is greater than

mod sithara negative skewed

the empirical relation is mean is

less than median and median is less than

more according to carl pearson

in case of moderately skewed

or moderately asymmetrical distribution

the value of the mean

median and mode have the

following empirical relations in case of

relation

mean minus mode is equal to

3 into a negative

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GDB STA 301 Fall 2020 solution GDB STA301 solution fall 2020 virtual university vu

[Nazir Ahmad]

Iska solution kesy dena ha koi bta dy. Theory details me ya ko table b bnana ha

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STA301 GDB Solution Fall 2020

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STA301_GDB_Solution_Fall_2020

[+ M.Tariq Malik]

Sta301 GDB Solution 2020

[+ M.Tariq Malik]

#sta301gdb1solutionfall2020 #sta301gdbsolution2020
STA301 GDB 1 Solution Fall 2020 | STA301 GDB 1 Solution

[Muhammad Bilal]

I think the solution given by sir Tariq is correct

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STA301 GDB 1 2020 solution Due Date 26-11-2020

[+ M.Tariq Malik]

STA301 GDB Solution

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STA301 GDB Solution Fall 2020

[+ M.Tariq Malik]

STA-301 
GDB No 1 Solution 
2020 
Requirement:
What can you say of the
skewness  in each of the following cases?
1-    Mode= 32.1 & Mean= 35.4
2-    Median= 1459 & Mean= 1403
3-    Median= 50 & Mean= 50
Answer:
Mode = 3Median - 2Mean
32.1 = 3Median – 2(35.4)
32.1 =  3Median – 70.8
32.1 + 70.8 = 3Median
102.9 = 3Median
102.9 / 3 = Median
34.3 = Median 
Mean > Median > Mode
35.4 > 34.3 > 32.1Positive skewed distribution
Mode =  3Median - 2Mean
Mode = 3(1459) – 2(1403)
Mode = 4377 – 2806
Mode = 1571
Mean < Median < Mode
1403 > 1459 > 1571  Negative skewed distribution
Mode =  3Median - 2Mean
50 = 3(50) – 2Mean
50 = 150 – 2Mean
50 - 150= - 2Mean

-100 = - 2Mean
100 / 2 = Mean
50 = Mean
Mean = Median = Mode
50 = 50 = 50 Normal distribution

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#STA_301 1st GDB Solution Fall 2020
Don't copy paste.

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STA301 Solution File

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STA301_1st_gdb_solution_fall_2020.docx

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STA301 GDB solution 2020