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STA301 GDB Fall 2020 Solution & Discussion

skewed okay subsequently symmetrical distribution
in the case of symmetrical distribution
the empirical relation state that
those symmetrical distributions
mean
when our distribution is not symmetric
mean is greater than median and median
is greater than
mod sithara negative skewed
the empirical relation is mean is
less than median and median is less than
more according to carl pearson
in case of moderately skewed
or moderately asymmetrical distribution
the value of the mean
median and mode have the
following empirical relations in case of
relation
mean minus mode is equal to
3 into a negative


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GDB STA 301 Fall 2020 solution GDB STA301 solution fall 2020 virtual university vu

Iska solution kesy dena ha koi bta dy. Theory details me ya ko table b bnana ha

STA301 GDB Solution Fall 2020

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STA301_GDB_Solution_Fall_2020

Sta301 GDB Solution 2020

#sta301gdb1solutionfall2020 #sta301gdbsolution2020
STA301 GDB 1 Solution Fall 2020 | STA301 GDB 1 Solution

I think the solution given by sir Tariq is correct

STA301 GDB 1 2020 solution Due Date 26-11-2020

STA301 GDB Solution

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STA301 GDB Solution Fall 2020

STA-301 
GDB No 1 Solution 
2020 
Requirement:
What can you say of the
skewness  in each of the following cases?
1-    Mode= 32.1 & Mean= 35.4
2-    Median= 1459 & Mean= 1403
3-    Median= 50 & Mean= 50
Answer:
Mode = 3Median - 2Mean
32.1 = 3Median – 2(35.4)
32.1 =  3Median – 70.8
32.1 + 70.8 = 3Median
102.9 = 3Median
102.9 / 3 = Median
34.3 = Median 
Mean > Median > Mode
35.4 > 34.3 > 32.1Positive skewed distribution
Mode =  3Median - 2Mean
Mode = 3(1459) – 2(1403)
Mode = 4377 – 2806
Mode = 1571
Mean < Median < Mode
1403 > 1459 > 1571  Negative skewed distribution
Mode =  3Median - 2Mean
50 = 3(50) – 2Mean
50 = 150 – 2Mean
50 - 150= - 2Mean

-100 = - 2Mean
100 / 2 = Mean
50 = Mean
Mean = Median = Mode
50 = 50 = 50 Normal distribution

#STA_301 1st GDB Solution Fall 2020
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STA301 Solution File

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