We have been working very hard since 2009 to facilitate in your learning Read More. We can't keep up without your support. Donate Now.

www.bit.ly/vucodes

+ Link For Assignments, GDBs & Online Quizzes Solution

www.bit.ly/papersvu

+ Link For Past Papers, Solved MCQs, Short Notes & More

(a) The number of traffic accidents that occurs on a particular stretch of road during a month follows a Poisson distribution with a mean of 9.4. Find the probability that less than four accidents will occur on this stretch of road during a randomly selected month.

(b) Twelve people apply for a job as Lecturer in a College. Eight have completed graduation and four have not. If the Principal selects five applications at random, find the probability that three are graduate and two are not.


+ http://bit.ly/vucodes (Link for Assignments, GDBs & Online Quizzes Solution)

+ http://bit.ly/papersvu (Link for Past Papers, Solved MCQs, Short Notes & More)

+ Click Here to Search (Looking For something at vustudents.ning.com?)

+ Click Here To Join (Our facebook study Group)


Views: 2422

Replies to This Discussion

Anybody ha

he number of traffic accidents that occurs on a particular stretch of road during a month follows a Poisson distribution with a mean of 9.4. Find the probability that less than two accidents will occur on this stretch of road during a randomly selected month.

Solution:

P(x < 2) = P(x = 0) + P(x = 1)

Ans: 0.000860

X not X N(X) P(X) X*P(X) Σ (N) Σ (P) 
----- ----- ------------ ------------- -------------- ------------- -------------- 
1 4 8 1/99 0.0101 8 0.010101010101 
2 3 112 14/99 0.2828 120 0.151515151515 
3 2 336 14/33 1.2727 456 0.575757575757 
4 1 280 35/99 1.4141 736 0.929292929292 
5 0 56 7/99 0.3535 792 1 
------------ ------------- -------------- ------------- -------------- 
totals: 792 1 3.3333 

Answer: 14/33

Solution:
a)
The Poisson distribution is,
P(x=x) =e-xx/x! (x=0, 1, 2, 3…)
Here =9.4
P(x<4) =? P(x<4) =P(x=0) +P(x=1) +P(x=2) +P(x=3) P(x<4) =0.000083+0.00078+0.0037+0.0115 P(x, 4) =0.01606 Solution:- b) The hyper geometric p.d is P(x=x) =kcxN-kcn-x/Ncn Here N=12 k=8 n=5 P(x=3 are graduate & two are not) =? =8c3 4c2/12c5 = 56*6/792 = 336/792 =0.4242

Thanks dosary ka b solution du

How to Post Math Subjects GDB On GDB Interface using Mathtype 6.9 

sta301 gdb complete solution

Attachments:

Please Discuss here about this assignment.Thanks

Our main purpose here discussion not just Solution

We are here with you hands in hands to facilitate your learning and do not appreciate the idea of copying or replicating solutions.

RSS

Looking For Something? Search Here

HELP SUPPORT

This is a member-supported website. Your contribution is greatly appreciated!

© 2020   Created by +M.Tariq Malik.   Powered by

Promote Us  |  Report an Issue  |  Privacy Policy  |  Terms of Service

.