We are here with you hands in hands to facilitate your learning & don't appreciate the idea of copying or replicating solutions. Read More>>

www.vustudents.ning.com

 www.bit.ly/vucodes + Link For Assignments, GDBs & Online Quizzes Solution www.bit.ly/papersvu + Link For Past Papers, Solved MCQs, Short Notes & More

# STA301 GDB Last Date 20 July 2016

(a) The number of traffic accidents that occurs on a particular stretch of road during a month follows a Poisson distribution with a mean of 9.4. Find the probability that less than four accidents will occur on this stretch of road during a randomly selected month.

(b) Twelve people apply for a job as Lecturer in a College. Eight have completed graduation and four have not. If the Principal selects five applications at random, find the probability that three are graduate and two are not.

+ How to become Top Reputation, Angels, Intellectual, Featured Members & Moderators?

+ VU Students Reserves The Right to Delete Your Profile, If?

Views: 2376

.

+ http://bit.ly/vucodes (Link for Assignments, GDBs & Online Quizzes Solution)

+ http://bit.ly/papersvu (Link for Past Papers, Solved MCQs, Short Notes & More)

### Replies to This Discussion

Anybody ha

he number of traffic accidents that occurs on a particular stretch of road during a month follows a Poisson distribution with a mean of 9.4. Find the probability that less than two accidents will occur on this stretch of road during a randomly selected month.

Solution:

P(x < 2) = P(x = 0) + P(x = 1)

Ans: 0.000860

X not X N(X) P(X) X*P(X) Σ (N) Σ (P)
----- ----- ------------ ------------- -------------- ------------- --------------
1 4 8 1/99 0.0101 8 0.010101010101
2 3 112 14/99 0.2828 120 0.151515151515
3 2 336 14/33 1.2727 456 0.575757575757
4 1 280 35/99 1.4141 736 0.929292929292
5 0 56 7/99 0.3535 792 1
------------ ------------- -------------- ------------- --------------
totals: 792 1 3.3333

Solution:
a)
The Poisson distribution is,
P(x=x) =e-xx/x! (x=0, 1, 2, 3…)
Here =9.4
P(x<4) =? P(x<4) =P(x=0) +P(x=1) +P(x=2) +P(x=3) P(x<4) =0.000083+0.00078+0.0037+0.0115 P(x, 4) =0.01606 Solution:- b) The hyper geometric p.d is P(x=x) =kcxN-kcn-x/Ncn Here N=12 k=8 n=5 P(x=3 are graduate & two are not) =? =8c3 4c2/12c5 = 56*6/792 = 336/792 =0.4242

Thanks dosary ka b solution du

How to Post Math Subjects GDB On GDB Interface using Mathtype 6.9

sta301 gdb complete solution

Attachments:

Our main purpose here discussion not just Solution

We are here with you hands in hands to facilitate your learning and do not appreciate the idea of copying or replicating solutions.

## Latest Activity

5 minutes ago
Ishaal Saifi posted a discussion

### Ms

10 minutes ago
20 minutes ago
+ "αяsαℓ " Ќąƶµяɨ •" left a comment for MALIK G
21 minutes ago
+ "αяsαℓ " Ќąƶµяɨ •" left a comment for IBS
22 minutes ago
+ Iuuoɔǝut+ posted discussions
46 minutes ago
46 minutes ago
51 minutes ago
58 minutes ago
1 hour ago
Whispering Soul liked Whispering Soul's discussion شاہی جوڑے کی رکشہ میں آمد
1 hour ago
Whispering Soul posted a discussion

### شاہی جوڑے کی رکشہ میں آمد

1 hour ago
1 hour ago
1 hour ago
1 hour ago
1 hour ago
+ "αяsαℓ " Ќąƶµяɨ •" left a comment for Ƨ.ℳƧℂƧ
1 hour ago
+ "αяsαℓ " Ќąƶµяɨ •" left a comment for stylo
1 hour ago
1 hour ago
1 hour ago

1

2

3