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# STA301_Spring_2012_Assigenment_IDea_solution.

STA301_Spring_2012_Assigenment_IDea_solution.pdf

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PLEASE MENTION HERE IF YOU FIND ANY MISTAKE IN THIS SOLUTION

dear sara solution ghalat hy....apka

Class limits ka interval 5 ka lena hay

jo k ye banta hay

20-24

5 me 20 or 24 include hty hain ok...20-25 ye interval 6 ka hy

amir ka bhi or apka bhi sara solution wrong hy

Mera solution check kro.......

yes main nae chk kia hae

apna to boht he bary mistek kia hae jo nae kerna wali dear g

:)

apna jo F2 ki value li hae wo he wrong li hae

apna F2 ki value 2 li hae lakan value 8 hae

what is class boundaries?

class boundaries = upper class - lower class / 2

here is this case 25 is upper class and 24 is lower hence

25-24/2 which is equal to 0.5

now we will deduct 0.5 from 20 and will add 0.5 to 24 to get class boundaries

for example

our class limit is

20-24

now we will

20-0.5--------24+0.5

which will be 19.5---24.5 this is the method to convert class limits and class boundaries

Note:

Class interval is 5

so we will make a class from 20-24

because 20,21,22,23,24 these are five which is our limit. not 20-25 it will be 6 limit

So the correct class limit is 20-24

Now lets talk about the second question

The same method we will use to get class boundaries

0.7314-0.7313/2=0.0005

now we will decrease 0.00005 from 0.7312 and we will add 0.00005 to 0.7313 same like that we will make class boundaires for every class limits

and for MODE we will take modal class

now

What is Modal Class?

Modal class is that class in which ur maximum frequency lie. Here in this case 30 is the maximum frequecny and its class is modal class and the frequency which is exectly above 30 will be called as F1 and frequecy exct below the 30 will be called as F2

Thanks and Best Regards

Abdul Rehman Ansari

0.0001/2= interval

Abdul Rehman Ansari

thanks apna bata dia

lakan dear g kesi ko wrong nae khtye

apna jo assignment ka solution upload kia hae wo b wrong hae

ager ap kaho to main apko bta data hun ????

tnxx

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