STA301_Spring_2012_Assigenment_IDea_solution.pdf
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PLEASE MENTION HERE IF YOU FIND ANY MISTAKE IN THIS SOLUTION
dear sara solution ghalat hy....apka
Class limits ka interval 5 ka lena hay
jo k ye banta hay
20-24
5 me 20 or 24 include hty hain ok...20-25 ye interval 6 ka hy
amir ka bhi or apka bhi sara solution wrong hy
Mera solution check kro.......
yes main nae chk kia hae
apna to boht he bary mistek kia hae jo nae kerna wali dear g
:)
apna jo F2 ki value li hae wo he wrong li hae
apna F2 ki value 2 li hae lakan value 8 hae
what is class boundaries?
class boundaries = upper class - lower class / 2
here is this case 25 is upper class and 24 is lower hence
25-24/2 which is equal to 0.5
now we will deduct 0.5 from 20 and will add 0.5 to 24 to get class boundaries
for example
our class limit is
20-24
now we will
20-0.5--------24+0.5
which will be 19.5---24.5 this is the method to convert class limits and class boundaries
Note:
Class interval is 5
so we will make a class from 20-24
because 20,21,22,23,24 these are five which is our limit. not 20-25 it will be 6 limit
So the correct class limit is 20-24
Now lets talk about the second question
The same method we will use to get class boundaries
0.7314-0.7313/2=0.0005
now we will decrease 0.00005 from 0.7312 and we will add 0.00005 to 0.7313 same like that we will make class boundaires for every class limits
and for MODE we will take modal class
now
What is Modal Class?
Modal class is that class in which ur maximum frequency lie. Here in this case 30 is the maximum frequecny and its class is modal class and the frequency which is exectly above 30 will be called as F1 and frequecy exct below the 30 will be called as F2
Thanks and Best Regards
Abdul Rehman Ansari
0.0001/2= interval
Abdul Rehman Ansari
thanks apna bata dia
lakan dear g kesi ko wrong nae khtye
apna jo assignment ka solution upload kia hae wo b wrong hae
ager ap kaho to main apko bta data hun ????
tnxx
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