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Quiz no.2 | Dated: Feb 01, 13 |
You are informed that Quiz no.2 will be started according to the following schedule; Opening Date and Time of Quiz Feb 14, 2013 at 12:01AM Instructions: Read the following instructions carefully before attempting the Quiz No.2. • It is advised that for rough work keep a paper and pencil with you. • You may use calculator for finding the correct solution among options. • If any student failed to attempt the quiz in given time then NO re-take or offline quiz will be held. |
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Chapter No 27 to 30
Chapter No 33 to 35
Chapter No 40 to 43
Total Chapter 11
Total Quizzes 10
So = 10/11 = 0.90909090909090909090909090909091 = 0.909091% Chance today
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In a chi-square distribution, if Variance is 9 then value of mean will be:
In general, the estimators obtained by the method of moments are ………….
A confidence interval has a specified probability__________ of containing the true value of the parameter.
The precision of an estimator can be increased by decreasing the;
In a Poisson distribution, Maximum Likelihood Estimator (MLE) for meu (u) is equal to:
We can apply method of Maximum Likelihood on:
If b(x, 7, 0.30), the variance of this distribution is:
“The temperatures of patients were checked before and after given a certain medicine.” This is an example of:
Natural pairing of data
Pairing by design
Which of the following must not be a consistent estimator
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Question # 1 of 10 (Start time: 06:44:02 PM) Total Marks: 1
In the method of moments, how many equations are required for finding two unknown population parameters?
Select correct option:
Question # 2 of 10 (Start time: 06:45:31 PM) Total Marks: 1
For statistical inference about the mean of a single population when the population standard deviation is unknown, the degrees for freedom for the t distribution equal n-1 because we lose one degree of freedom by using the:
Select correct option:
Sample mean as an estimate of the population mean
Sample size as an estimate of the population size
Sample proportion as an estimate of the population proportion
Sample standard deviation as an estimate of the population standard deviation
Question # 3 of 10 ( Start time: 06:47:31 PM ) Total Marks: 1
An urn contains 4 red balls and 6 green balls. A sample of 4 balls is selected from the urn without replacement. It is the example of:
Select correct option:
Binomial distribution
Hypergeometric distribution
Poisson distribution
Exponential distribution
Question # 4 of 10 ( Start time: 06:48:17 PM ) Total Marks: 1
An estimator is always a:
Select correct option:
Statistic
Random variable
Statistic and Random variable
Parameter
Question # 5 of 10 ( Start time: 06:49:50 PM ) Total Marks: 1
The Chi- Square distribution is continuous distribution ranging from:
Select correct option:
Zero to infinity
Minus infinity to plus infinity
Minus infinity to one
One to plus infinity
Question # 6 of 10 ( Start time: 06:51:10 PM ) Total Marks: 1
In a Geometric distribution, Maximum Likelihood Estimator (MLE) for proportion (P) is equal to:
Select correct option:
Sample mean
Reciprocal of the mean
Sample variance
Reciprocal of the sample variance
Question # 7 of 10 ( Start time: 06:52:45 PM ) Total Marks: 1
Let X be a random variable with binomial distribution, that is (x=0,1,…, n). The Var[X] is:
Select correct option:
P
NP
NP (1-p)
Xnp
Question # 8 of 10 ( Start time: 06:54:23 PM ) Total Marks: 1
ANOVA stands for
Select correct option:
Analysis of variance
Analysis of covariance
Analysis of variables
All above
Question # 9 of 10 ( Start time: 06:55:37 PM ) Total Marks: 1
If an estimator is more efficient then the other estimator, its shape of the sampling distribution will be
Select correct option:
Flattered
Normal
Highly peaked
Skewed to right
Question # 10 of 10 ( Start time: 06:56:34 PM ) Total Marks: 1
How can we interpret the 90% confidence interval for the mean of the normal population?
Select correct option:
There are 10% chances of falling true value of the parameter
There are 90% chances of falling true value of the parameter
There are 100% chances of falling true value of the parameter
All are correct
Question # 1 of 10 ( Start time: 07:03:59 PM ) Total Marks: 1
If a random variable X denotes the number of heads when we toss a fair coin 5 times, the X assumed the values:
Select correct option:
0,1,2,3
1, 2,3,4,5
0, 1, 2,3,4,5
1, 5, 5
Question # 2 of 10 ( Start time: 07:04:50 PM ) Total Marks: 1
Which of the following is most important and most widely used method in point estimation?
Select correct option:
The method of moments
The method of fractional moments
The method of least square
The method of maximum likelihood
The method of maximum likelihood is regarded as the MOST important method of estimation, and is the most widely used method. This method was introduced in 1922 by Sir Ronald A. Fisher (1890-1962).The mathematical technique of finding Maximum Likelihood Estimators is a bit advanced, and involves the concept of the Likelihood Function.
Question # 3 of 10 ( Start time: 07:05:41 PM ) Total Marks: 1
F-distribution is skewed to the
Select correct option:
Right
Left
Right and Left
None of these
Question # 4 of 10 ( Start time: 07:06:49 PM ) Total Marks: 1
As sample size goes up, what tends to happen to 95% confidence intervals?
Select correct option:
They become wider
They become more precise
They become more narrow
They become more precise and narrow
Question # 5 of 10 ( Start time: 07:08:10 PM ) Total Marks: 1
In a Geometric distribution, Maximum Likelihood Estimator (MLE) for proportion (P) is equal to:
Select correct option:
Sample mean
Reciprocal of the mean
Sample variance
Reciprocal of the sample variance
Question # 6 of 10 ( Start time: 07:09:29 PM ) Total Marks: 1
In general, the estimators obtained by the method of moments are ………….
Select correct option:
Biased
Inconsistent
Inefficient
All the above
Question # 7 of 10 ( Start time: 07:10:49 PM ) Total Marks: 1
When we draw the sample with replacement, the probability distribution to be used is:
Select correct option:
Binomial
Hypergeometric
Binomial & hypergeometric
Poisson
Question # 8 of 10 ( Start time: 07:11:28 PM ) Total Marks: 1
ANOVA stands for
Select correct option:
Analysis of variance
Analysis of covariance
Analysis of variables
All above
Question # 9 of 10 ( Start time: 07:12:00 PM ) Total Marks: 1
Suppose 60% of a herd of cattle is infected with a particular disease. Let Y = the number of non-diseased cattle in a sample of size 5. The distribution of Y is:
Select correct option:
Binomial with n = 5 and p = 0.6
Binomial with n = 5 and p = 0.4
Binomial with n = 5 and p = 0.5
Poisson with u = .6
Question # 10 of 10 (Start time: 07:13:04 PM) Total Marks: 1
The value of chi square can never be:
Select correct option:
Zero
Less than 1
Greater than 1
Negative
Question # 1 of 10 ( Start time: 07:28:04 PM ) Total Marks: 1
We use the Poisson approximation to the binomial when:
Select correct option:
p is 0.01 or less & n is 10
p is 0.05 or less & n is 50
p is 0.04 or less & n is 15
p is 0.02 or less & n is 10
Question # 2 of 10 ( Start time: 07:29:12 PM ) Total Marks: 1
In a Geometric distribution, Maximum Likelihood Estimator (MLE) for proportion (P) is equal to:
Select correct option:
Sample mean
Reciprocal of the mean
Sample variance
Reciprocal of the sample variance
Question # 3 of 10 ( Start time: 07:29:39 PM ) Total Marks: 1
If b(x; 15, 0.75), the mean of this distribution is:
Select correct option:
11.50
11.15
11.20
11.25
Question # 4 of 10 ( Start time: 07:31:02 PM ) Total Marks: 1
Under which of the following circumstances is it impossible to construct a confidence interval for the population mean?
Select correct option:
A normal population with a large sample and a known population variance
A non-normal population with a large sample and an unknown population variance
A normal population with a large sample and a known population variance
A non-normal population with a small sample and an unknown population variance
Question # 5 of 10 ( Start time: 07:32:27 PM ) Total Marks: 1
In completely randomized design (CRD) treatments are assigned to experimental units completely at random, i.e. randomization is done without any?
Select correct option:
Objection
Restriction
Obligation
All above mentioned
Question # 6 of 10 ( Start time: 07:33:42 PM ) Total Marks: 1
If the random variable “X” follows F-distribution with v1 and v2 degrees of freedom, then reciprocal of “X” i.e. “1/X” also follows F-distribution with respective degrees of freedom
Select correct option:
v1
v2
V1 and v2
V2 and v1
Question # 7 of 10 ( Start time: 07:35:02 PM ) Total Marks: 1
The precision of an estimator can be increased by decreasing the;
Select correct option:
Level of significance
Number of parameters
Number of estimators
Size of sample
Question # 8 of 10 ( Start time: 07:36:28 PM ) Total Marks: 1
T-distribtion is applicable in case of
Select correct option:
Independent samples
Dependent samples
Both independent and dependent samples
Non-Normal populations
Question # 9 of 10 ( Start time: 07:37:49 PM ) Total Marks: 1
A consistent estimator will always be a:
Select correct option:
Unbiased estimator
Biased estimator
Unbiased estimator and biased estimator
May or may not be unbiased estimator
Question # 10 of 10 ( Start time: 07:39:15 PM ) Total Marks: 1
Which of the following is desirable for a good point estimator?
Select correct option:
Consistency
Unbiasedness
Efficiency
All of these
Question # 1 of 10 ( Start time: 07:45:27 PM ) Total Marks: 1
Suppose 60% of a herd of cattle is infected with a particular disease. Let Y = the number of non-diseased cattle in a sample of size 5. the distribution of Y is:
Select correct option:
Binomial with n = 5 and p = 0.6
Binomial with n = 5 and p = 0.4
Binomial with n = 5 and p = 0.5
Poisson with u = .6
Question # 2 of 10 ( Start time: 07:45:46 PM ) Total Marks: 1
If b(x; 15, 0.75), the mean of this distribution is:
Select correct option:
11.50
11.15
11.20
11.25
Question # 3 of 10 ( Start time: 07:46:40 PM ) Total Marks: 1
A statistic whose standard deviation decreases with an increase in sample size will be called:
Select correct option:
Unbiased
Consistent
Efficient
Sufficient
Question # 4 of 10 ( Start time: 07:48:04 PM ) Total Marks: 1
F- Distribution has………parameter(s).
Select correct option:
One
Two
Three
No
Question # 5 of 10 ( Start time: 07:49:33 PM ) Total Marks: 1
In an ANOVA test there are 8 observations in each of 3 treatments. The degree of freedom for error in CR design is:
Select correct option:
21
24
14
16
Question # 6 of 10 ( Start time: 07:50:44 PM ) Total Marks: 1
What is the mean and variance of binomial distribution b(x; n, p)?
Select correct option:
Xp and npq
NP and PQ
NP and npq
Zero and one
Question # 7 of 10 ( Start time: 07:52:08 PM ) Total Marks: 1
“A point estimate plus/minus a few times the standard error of that estimate”. This statement represents:
Select correct option:
Confidence interval
Critical region
Acceptance region
Critical value
Question # 8 of 10 ( Start time: 07:53:20 PM ) Total Marks: 1
Mean of F-distribution with V2>2 is
Select correct option:
V1/(V2-2)
V2/(V2-2)
V2/(V1-2)
V1/(V1-2)
Question # 9 of 10 (Start time: 07:54:50 PM)
Which of the following is most important and most widely used method in point estimation?
Select correct option:
The method of moments
The method of fractional moments
The method of least square
The method of maximum likelihood
Question # 10 of 10 (Start time: 07:56:21 PM)
The hypergeometric random variable is a (an):
Select correct option:
Continuous variable
Discrete variable
Undefined
Independent
Which of the following statements is false?
The t distribution is symmetric about zero
The t distribution is more spread out than the standard normal distribution
As the degrees of freedom get smaller, the t-distribution’s dispersion gets smaller
The t distribution is mound-shaped
For statistical inference about the mean of a single population when the population standard deviation is unknown, the degrees for freedom for the t distribution equal n-1 because we lose one degree of freedom by using the:
Sample mean as an estimate of the population mean
Sample standard deviation as an estimate of the population standard deviation
Sample proportion as an estimate of the population proportion
Sample size as an estimate of the population size
In testing the hypotheses Null hypothesis: mu = 200
Alternative hypothesis: mu less than 200 the sample mean are found to be 120. The null hypothesis:
Should be rejected
Should not be rejected
Should be rejected only if n > 30
None of the above answers is correct
For a sample of size 20 taken from a normally distributed population with standard deviation equal to 5, a 90% confidence interval for the population mean would require the use of:
t = 1.328
t = 1.729
t = 2.12
z = 1.645
Under which of the following circumstances is it impossible to construct a confidence interval for the population mean?
A non-normal population with a large sample and an unknown population variance
A normal population with a large sample and a known population variance
Non-normal population with a small sample and an unknown population variance
A normal population with a small sample and an unknown population variance
Suppose that a one-tail t test is being applied to find out if the population mean is less than 100. The level of significance is .05 and 25 observations were sampled. The rejection region is:
t > 1.708
t < -1. 711
t > 1.318
t < -1.316
Which of the following is true about the t distribution?
Approaches the normal distribution as its degrees of freedom increase
Assumes the population is normally distributed
It is more spread out than the standard normal distribution
All of the above statements are true
A random sample of size 20 taken from a normally distributed population resulted in a sample variance of 32. The lower limit of a 90% confidence interval for the population variance would be:
52.185
20.375
20.170
54.931
A random sample of size 15 taken from a normally distributed population revealed a sample mean of 75 and a sample variance of 25. The upper limit of a 95% confidence interval for the population mean would equal:
77.769
72.231
72.727
77.273
Based on sample data, the 90% confidence interval limits for the population mean are LCL = 170.86 UCL = 195.42. If the 10% level of significance were used in testing the hypotheses
Null: mu = 201
Alt: mu not equal to 201, the null hypothesis:
Would be rejected
Would not be rejected
Would have to be revised
None of the above
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