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# STA301 Today Final Term Paper 19-07-2012

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Great effort....God bless u

thanks alot ............ God Bless You

sta301 paper on sun.

mostly mcqs were frm past papers some were new.

hypothesis

frequency destribution se related question that

probability se related numerical question tha

testing

bki bholl gya

best of luck to all of u remember me in ur prayers.

Solutions of the Following Questions Required Urgently

4. find value of A in joint probabilty of f(x,y) for exp AY-x/2 whereas 0<y<1, 0<x<1.

1.A random variable X is normally distributed with. Find the probability of x larger than 54.

2.A random sample of 50 observations is drawn from a normal distribution with. Suppose that the sample mean is found to be Find 95% confidence interval for

3.Find the value of chi-square from the following table.

 Number of Customer Arrivals Observed Frequency oi Expected Frequency ei 0 84 54.12 1 114 108.28 2 70 108.28 3 60 72.16 4 32 36.08 5 16 14.44 6 15 4.80 7 4 1.36 8 5 0.36 9 or more 0 0.08

4.Construct a stem-and-leaf display from the following data.

48, 31, 54, 37, 18, 64, 61, 43,

40, 71, 51, 12, 52, 65, 53, 42,

39, 62, 74, 48, 29, 67, 30, 49,

68, 35, 57, 26, 27, 58.

5.The p. d. f.  of a r.v. is given

Calculate P(X<0.5)

6.If population proportions are given as:

Find    ,where n = 10

7.Formulate the null and alternative hypothesis in each of the following.

(1) Average domestic consumption of electricity is 50 units per month.

(2) Not more than 30% people pay Zakat (tax).

10.An exercise physiologist wants to demonstrate that the average person walks more than 800 km per year. State the null and alternative hypothesis.

husband and wife apply for same job and husband probability for job is like this 9/3 and wife job probability was something 3/5 like , what is the probability that husband could get job and wife not?

a boy sell umbrellas on rainy days and earn 30\$ and in other days he can earn 24\$ , if the probability of rain is 0.3% what will he expectation ?

Q:The 90% confidence interval for the population mean is 11 to 20, interpret this result? 3 MarksQ:Define LSD test? 3 Marks

If an automobile is driven on the average no more than 16000 Km per year then formulate the null and alternative hypothesis (2)

If the population proportions are gives as: P1 = 0.4, P2 = 0.20
find sigma^2 P-hat 1 - P-hat 2 , where n = 12.

The probability density function of a random variable X is given by :
f(x) 3x^2 ( 0 < or equal to x is < or equal to 1)
0 else where
calculate P(X < 0.5) (5)

Nine individual are chosen at random from a normal population and their weights in Kg are found to be 63, 64, 66, 67, 67, 68, 69, 69, 70 with mean weight 67 and standard deviation 2.345. Test the hypotheses c
Ho : mew = 66Kg. Using 5% level of significance. (5)

Two samples are drawn from two normal populations with the following information:
Lahore : n1 = 50, X-bar 1 = 14, s1 = 5
Karachi: n2 = 70, X-bar 2 = 12, s2 = 4
Construct the 95% confidence interval for the difference between the two population means. ( 5)

1. there was a question of hypothesis testing of H0:variane1<variencs2. values of s1,s2,n1,n2 was given

find the critical value of chi-square
a boy sell ambrellas on rainy days and earn 30\$ and in other days he can earn 24\$ , if the propability of rain is 0.3% what will he expectation ?
some data was given,find P(X>25)

1. A sample of siz n=3 drawn without replacement expirenment from a population N=5 items whose values ,0,2,3,6,7 draw possible samples

2. Calculate sampling error if sample is 102 and population mean is 100

3. A random sample of 12 observations is drawn then a normal distribution with =33.suppose that the sample means is found to be Find 96% confidence interval for

1. A sample of siz  n=3 drawn without replacement expirenment from a population  N=5 items whose values ,0,2,3,6,7 draw  possible samples
2. Calculate sampling error  if sample is 102 and population mean is 100
3. A random sample of  12 observations is drawn  then a normal distribution  with =33.suppose that the  sample means  is found to be  Find 96% confidence interval for
4. RCBD with MSE=200Measure of treatments=4 no of block=5  Then find value of LSD  test for

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